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Lelechka [254]
4 years ago
10

A box is 26 inches wide, 5 inches tall, volume of 1170 in.³. What is the length of the box?

Mathematics
1 answer:
serg [7]4 years ago
7 0
V=LWH
V=1170
L=?
W=26
H=5
1170=? times 26 times 5
1170=? times 130
divide both sides by 130
9=?

legnth=9inches
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1. Complete the problem by using your calculator. Round your answer to three decimal places.
DaniilM [7]

Answer:

c.

Step-by-step explanation:

Plug in -2 for x ....

f(x) = -2^3 - 7(-2)^2 + 3

     = -8 - 28 + 3

     = -36 + 3

     = -33

Plug in 3/4 for x ....

f(x) = 3/4^3 - 7(3/4)^2 + 3

     = 27/64 - 63/16 + 3

The put in decimals ....

27/64 = .422

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Put the decimals back into the equation ....

     = .422 - 3.938 + 3

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3 0
3 years ago
Which point is 7 units from (–2, 4)?
Serjik [45]
The distance formula:
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(-2,4) \\
d=7 \\ \\
7=\sqrt{(x-(-2))^2+(y-4)^2} \\
7=\sqrt{(x+2)^2+(y-4)^2} \ \ \ |^2 \\
49=(x+2)^2+(y-4)^2
Check which point satisfies the equation:
(x,y)=(-5,4) \\
49 \stackrel{?}{=} (-5+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} (-3)^2+0^2 \\
49 \stackrel{?}{=} 9 \\
49 \not= 9 \\
doesn't \ satisfy \ the \ equation

(x,y)=(-2,3) \\
49 \stackrel{?}{=} (-2+2)^2+(3-4)^2 \\
49 \stackrel{?}{=} 0^2+(-1)^2 \\
49 \stackrel{?}{=} 1 \\
49 \not= 1 \\
doesn't \ satisfy \ the \ equation

(x,y)=(5,4) \\
49 \stackrel{?}{=} (5+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} 7^2+0^2 \\
49 \stackrel{?}{=} 49 \\
49=49 \\
satisfies \ the \ equation

(x,y)=(9,4) \\
49 \stackrel{?}{=} (9+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} 11^2+0^2 \\
49 \stackrel{?}{=} 121 \\
49 \not= 121 \\
doesn't \ satisfy \ the \ equation

The answer is C.
3 0
4 years ago
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OleMash [197]

Answer:

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Step-by-step explanation:

1/9 =1/4hr

9/9=x

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1/9=1/4.xhr

cross multiplying

4x=9

x=9/4

x=2.25hrs

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8 21/100 is the mixed number for8.21
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sergejj [24]
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3 0
3 years ago
Read 2 more answers
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