Let z = sin(x).
.. z^2 -2z = 2
.. z^2 -2z +1 = 3
.. (z -1)² = 3
.. z -1 = ±√3
.. z = 1 -√3 . . . . . the positive solution is extraneous
sin(x) = 1 -√3
L=2w-3
w(2w-3)=54
2w²- 3w-54=0
A= 2 , B= -3, C= -54
sub values into quadratic formula
i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check:
L=2w-3
=2(6)-3
=12-3
=9
9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm
Answer:
we can proove by ASA congruence or SAS congruence rule