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4 years ago

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Column proof for 3x-10 and 2x+5

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Mice21 [21]4 years ago

6 0

were are the answer choices

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Find the height of the pyramid.

SOVA2 [1]

Answer:

7

Step-by-step explanation:

Let the height of pyramid be h

$v = \frac{1}{3} lwh$

v= 224

w= 8

l= 12

224=1/3(12)(8)(h)

224=32h

h=224/32

h=7

4 0

3 years ago

A triangle has vertices of (–2, –1), (0, –5), and (3, 2). What are the vertices of the image after applying the translation 2004

marysya [2.9K]

The triangle translated up would have vertices at S(1,4), T(2,0), and U(4,3).

7 0

3 years ago

What is the inverse of f(x) = 6x -24

hammer [34]

Answer:

f^(−1)(x)= x/6+4

Step-by-step explanation:

interchange the variables and solve for

y

6 0

3 years ago

Consider the following initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy = 0, y(1) = 1 Let ∂f ∂x = (x + y)2 = x2 + 2xy + y2

IRISSAK [1]

$(x+y)^2\,\mathrm dx+(2xy+x^2-2)\,\mathrm dy=0$

Suppose the ODE has a solution of the form $F(x,y)=C$ , with total differential

$\dfrac{\partial F}{\partial x}\,\mathrm dx+\dfrac{\partial F}{\partial y}\,\mathrm dy=0$

This ODE is exact if the mixed partial derivatives are equal, i.e.

$\dfrac{\partial^2F}{\partial y\partial x}=\dfrac{\partial^2F}{\partial x\partial y}$

We have

$\dfrac{\partial F}{\partial x}=(x+y)^2\implies\dfrac{\partial^2F}{\partial y\partial x}=2(x+y)$

$\dfrac{\partial F}{\partial y}=2xy+x^2-2\implies\dfrac{\partial^2F}{\partial x\partial y}=2y+2x=2(x+y)$

so the ODE is indeed exact.

Integrating both sides of

$\dfrac{\partial F}{\partial x}=(x+y)^2$

with respect to $x$ gives

$F(x,y)=\dfrac{(x+y)^3}3+g(y)$

Differentiating both sides with respect to $y$ gives

$\dfrac{\partial F}{\partial y}=2xy+x^2-2=(x+y)^2+\dfrac{\mathrm dg}{\mathrm dy}$

$\implies x^2+2xy-2=x^2+2xy+y^2+\dfrac{\mathrm dg}{\mathrm dy}$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=-y^2-2$

$\implies g(y)=-\dfrac{y^3}3-2y+C$

$\implies F(x,y)=\dfrac{(x+y)^3}3-\dfrac{y^3}3-2y+C$

so the general solution to the ODE is

$F(x,y)=\dfrac{(x+y)^3}3-\dfrac{y^3}3-2y=C$

Given that $y(1)=1$ , we find

$\dfrac{(1+1)^3}3-\dfrac{1^3}3-2=C\implies C=\dfrac13$

so that the solution to the IVP is

$F(x,y)=\dfrac{(x+y)^3}3-\dfrac{y^3}3-2y=\dfrac13$

$\implies\boxed{(x+y)^3-y^3-6y=1}$

5 0

3 years ago

Help meeeeeeeeeeeeeeeeeeeeeeeeeeeee pleaseeeeeeeeeeeeee

olchik [2.2K]

Answer:

The quickest answer is to take the number 72 and divide it by the rate of interest. In this case, it would take approximately 72/6, or 12 years to double.

Step-by-step explanation:

5 0

1 year ago