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3 years ago

The relationship between the slopes of two lines that are parallel is _____________.

2 answers:

8 0

They are the same slope

they are negative inversees (they multily to get -1)

2

-1/2

use the square viewer (on TI)

The relationship between the slopes of two lines that are parallel is they are the same. The relationship between the slopes of two lines that are perpendicular is they are negative inverses of each other (they multiply to -1).
A line that is parallel to a line whose slope is 2 has slope 2.
A line that is perpendicular to a line whose slope is 2 has slope -1/2.

What must be done to make the graphs of two perpendicular lines appear to intersect at right angles when they are graphed using a graphing utility?

kvv77 [185]3 years ago

8 0

The slopes of 2 lines that are parallel will be the same. the slopes of 2 lines that are perpendicular will have negative reciprocal slopes.
parallel to a line with slope 2 is 2 (because parallel lines have the same slope). perpendicular to a line with slope 2 is -1/2 (the negative reciprocal...to find the negative reciprocal, just flip the slope of the original equation and change the sign)

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Generalize the pattern by finding the nth term.

Veseljchak [2.6K]

Answer:

4n+2

Step-by-step explanation:

The common difference between the terms is 4 which means that the sequence is an arithmetic sequence.

The general formula for arithmetic sequence is:

$a_{n}=a_{0}+(n-1)d$

where a_n is the nth term, a_0 is the first term and d is the common difference between them.

We know that

$a_{0}=6\\d=4$

Putting the value in general formula:

$a_{n}=6+4(n-1)\\a_{n}=6+4n-4\\a_{n}=4n+6-4\\a_{n}=4n+2\\$

So the generalized pattern is 4n+2 ..

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2 years ago

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Dafna11 [192]

Answer:

42°

Step-by-step explanation:

AD bisects ∠CAB, which means it splits ∠CAB into two equal parts. ∠CAB equals 84°. 84° ÷ 2 = 42°.

7 0

3 years ago

I really need help with this

ElenaW [278]

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1000/2+20/2=510
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3 years ago

Let the smallest of 4 consecutive odd numbers be 2 n + 1 , where n is an integer. Show, using algebra, that the sum of any 4 con

andrey2020 [161]

Answer:

Expression is 8(n+2)

Step-by-step explanation:

smallest of 4 consecutive odd numbers =2n + 1

consecutive odd integers are found by adding 2 to the any given odd numbers

Thus, 2nd consecutive odd integers = 2n + 1 + 2 = 2n + 3

3rd consecutive odd integers = 2n + 3 + 2 = 2n + 5

2nd consecutive odd integers = 2n + 5 + 2 = 2n + 7

Thus, 4 consecutive odd integers are

2n + 1 ,2n + 3,2n + 5,2n + 7

sum of these numbers are = 2n + 1 +2n + 3 + 2n + 5+2n + 7 = 8n+16

sum of these numbers are = 8(n+2)

Thus, we see that the sum of numbers are 8(n+2)

As, 8 is common for n+2, whatever is value of n, the number will be multiple of 8 .

thus expression is 8(n+2)

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2 years ago

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BabaBlast [244]

I think it would be A but I'm not sure ._.

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3 years ago