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3 years ago

The population of Medfield is 7000. Capital City's population is of Medfield's. What is Capital City's population?

Mathematics

1 answer:

snow_tiger [21]3 years ago

6 0

Since the Capital City's population is of Medfield's is 7000 please tell if you forgot something. Good luck

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1/4 divided by 5/6 = 1/a× b/c

motikmotik

Answer:

a= 24b/5c b= 5ac/24 c= 24b/5a

Step-by-step explanation:

Put the problem into a calculator that can solve with variables.

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3 years ago

The top of the John Hancock Building is a rectangle whose length is 60 ft more than the width. The perimeter is 520 feet. What i

statuscvo [17]

Answer:

160 ft

Step-by-step explanation:

We have

2(length + width)= perimeter

than,

let, width =x

now,

2(x+60+x) = 520

or, 2x+60 = 260

or, 2x = 200

or, x = 100

so length is 100+60 = 160

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2 years ago

kirza4 [7]

Each game was $44.99, if she spent a total of 284.97 and we subtract the cost of the console 284.97 - 194.99 = 89.98, since the two games were equally priced we divide 89.98/2 and get $44.98

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3 years ago

What is the slope-intercept equation of the line below? A.y=2x+3 B.y=-2x-3 C.y=2x-3 D.y=-2x+3

PtichkaEL [24]

Answer:

Step-by-step explanation:

First, lets find the y-intercept. The y-intercept where the line passes through the y-axis. In this case, it is -3.

Now, to find the slope, lets find the next non-decimal point(that way it is easier on us). That would be (1,-1). Now, to get to this point from the y-intercept, we have to go left 1 unit, and up 2 units. So, the change in y over change in x = 2/1 or 2. Now, using this information, we can form the equation:

y = 2x + -3. or y = 2x - 3.

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3 years ago

One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many

Phantasy [73]

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = $6.022\times 10^{23}$ sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

$\frac{6.022\times 10^{23}}{10^{12}}=6.022\times 10^{11}$

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of $6.022\times 10^{11}$ trillion sand particles is

$Mass=1000\times 6.022\times 10^{11}=6.022\times 10^{14}tonnes$

Part 2)

Since it is given that volume of 1 sand particle is $1.0mm^{3}$ thus the volume of 1 mole of sand is volume of $6.022\times 10^{23}$ sand particles

Thus volume of 1 mole is $V=1.00\times 10^{-18}km^{3}\times 6.022\times 10^{23}=6.022\times 10^{5}km^{3}$

Now since the Area of united states is $A=3.6\times 10^{6}mile^{2}=5.8\times 10^{6}km^{2}$

Thus the depth of the sand pile is

$Depth=\frac{Volume}{Area}=\frac{6.022\times 10^5}{5.8\times 10^6}=0.10387km=103.8meters$

4 0

3 years ago