2 years ago

Factoring Polynomials: 6-13a+6a^2

Mathematics

1 answer:

Firlakuza [10]2 years ago

6 0

(Factor by grouping 2-3a)(3-2a)

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The first term in a sequence of numbers is 1/2

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The correct answer is C. The 4th term is 11.

Step-by-step explanation:

Since the next term is one more than twice the previous, we can calculate it by the following expression:

$a_{n} = 2*a_{n-1} + 1$

So the second term is:

$a_2 = 2*\frac{1}{2} + 1\\a_2 = 2$

The third term:

$a_3 = 2*2 + 1\\a_3 = 5$

And the fourth term:

$a_4 = 2*5 + 1\\a_4 = 10 + 1 = 11$

The correct answer is C. The 4th term is 11.

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