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djverab [1.8K]
2 years ago
6

A car moving at a constant speed passed a timing device at t = 0. After 8 seconds, the car has traveled 936 ft. Write a linear f

unction rule to model the distance in feet d the car has traveled any number of seconds t after passing the timing device.​
Mathematics
2 answers:
Ahat [919]2 years ago
5 0

Answer:

Buenos días;

1) La ecuación de la velocidad en un movimiento uniformemente acelerado (M.U.A) es:

V=V₀+at.

V=30 m/s-2 m/s².t

Ahora elimina las unidades (m/s, m/s₂), y tendrás la ecuación de la velocidad en función del tiempo.  

V(t)=30-2t.

Sol: la ecuación de la velocidad en función del tiempo es : V(t)=30-2t.

2) La ecuación de la posición en función del tiempo en un M.U.A  es:

X=X₀+V₀.t+(1/2).a.t²

X=0+30 m/s.t+(1/2).(-2 m/s²).t²

Eliminas las unidades, y tendrás la ecuación de la posición en función del tiempo.

X(t)=30.t-t².

Sol: la ecuación de la posición en función del tiempo es: X(t):30t-t²

Un saludo.

Step-by-step explanatio:g

Leokris [45]2 years ago
5 0

Answer:

The required equation is:

  • d = 81t
  • f(t) = 81t

Step-by-step explanation:

I think that's the answer

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Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive
Ivan

Answer:

(a) The average cost function is \bar{C}(x)=95+\frac{230000}{x}

(b) The marginal average cost function is \bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose C(x) is a total cost function. Then the average cost function, denoted by \bar{C}(x), is

\frac{C(x)}{x}

We know that the total cost for making x units of their Senior Executive model is given by the function

C(x) = 95x + 230000

The average cost function is

\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}

(b) The derivative \bar{C}'(x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95

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A major baseball diamond is a square with side lengths of 90 feet.
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Answer: \bold{a)\quad 90\sqrt2\qquad \qquad b)\quad 45\sqrt2}

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Since you are looking for the distance from home plate to second base, you are actually looking for the length of the diagonal of the square.  Use the Pythagorean Theorem: a² + b² = c² where a and b are the side lengths and c is the length of the diagonal.

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