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3 years ago

Density describes the relationship between the and of a sample of a substance.

Mathematics

1 answer:

uysha [10]3 years ago

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destiny describes the relationship between the substance and volume of a sample of a substance it was little bit ez

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Dvide if the polynomial does not divide evenly. Include the remainder as a fraction (18u^2 - 142u - 11) ÷ (u - 8)

Mashutka [201]

Answer:

18u + 2 + 5/(u - 8)

Step-by-step explanation:

(18u^2 - 142u - 11) ÷ (u - 8)

18u^2 - 142u - 11 =
18u^2 - 8*18u + 2u - 11 =
18u(u - 8) + 2u - 16 + 5 =
18u(u - 8) + 2(u - 8) + 5 =
(18u + 2)(u - 8) + 5

(18u^2 - 142u - 11) ÷ (u - 8) = 18u + 2 + 5/(u - 8)

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3 years ago

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What is the answer to the problem 16g +20h with the distributed property applied

e-lub [12.9K]

36 g I’m pretty sure that’s the answer

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3 years ago

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If three parallel lines are cut by a transversal and one angle is measured to be 90 degrees, what can be said of the remaining?

V125BC [204]

Answer: A. There all 90 degrees

Step-by-step explanation:

Given: Three parallel lines are cut by a transversal and one angle is measured to be 90 degrees.

We know that if two lines cut by transversal the following pairs are equal:

Vertically opposite angles.
Corresponding angles.
Alternate interior angles.
Alternate exterior angles.

If one angles measures 90°, then its supplement would be 90°.

Then by using above properties , we will get measure of all angles as 90°.

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4 years ago

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You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along

sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

$d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}$

Then, the time (speed divided by distance) is:

$t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1$

To optimize this function we have to derive and equal to zero:

$\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\ \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\$

$x$

As $d_b=x$ , the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0

3 years ago

mina [271]

Answer:

y inversely proportional to 1/x

y=4, x=16

4=k/16

k=64

find y when x=8

y=64/8

y=8

3 0

3 years ago

Density describes the relationship between the ____________ and ____________ of a sample of a substance.

Density describes the relationship between the and of a sample of a substance.