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Doss [256]
2 years ago
6

Write an equation for the description

Mathematics
2 answers:
jeka942 years ago
8 0

Answer:

A) l = 2 * w

B) 131 = 2l + 2w

B) 2l = 131 -2w

B) l = 65.5 -w

Substituting this into A)

65.5 -w = 2w

3w = 65.5

width = 21.8333333333

length = 43.6666666666

Double - Check

131 = 2 * 21.833333333 + 2 * 43.6666666666

131  = 43.6666666  + 87.33333333

131 = 131

Step-by-step explanation:

MissTica2 years ago
5 0

Answer:

131=6w

Step-by-step explanation:

l=length\\\\w=width\\\\\Longrightarrow l=2w\\\\\Rightarrow Perimeter=l+l+w+w\\\\P=2l+2w\\\\P=2(2w)+2w\\\\P=4w+2w\\\\P=6w\\\\P=131\\\\131=6w\\\\w=\frac{131}{6}\\\\w=21.8\overline{3}\\\\l=43.\overline{6}

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How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
A game involves drawing a single card from a standard deck. One receives 60 cents for an ace, 30 cents for a king, and 5 cents f
professor190 [17]

Answer:

The expected game value is -1 cent

Step-by-step explanation:

Here, we want to calculate the expected value of the game

We have 4 aces and 4 kings, including 26 red cards

The number of aces is 4

Probability of drawing an ace is 4/52 = 1/13

Probability of drawing a king is also 4/52 = 1/13

There are 26 red cards

The number of red cards that are neither ace nor king

There are 2 red aces and 2 red kings

So the number of cards that are red but are not

aces nor kings are 26-2-2 = 22

The probability of selecting this is 22/52 = 11/26

So the expected value is simply the probability multiplied by the amount

Thus, we have;

(60 * 1/13) + (30 * 1/13) + (5 * 11/26)

= 60/13 + 30/13 + 55/26

= (120 + 60 + 55)/26 = 9.038 cents which is approximately 9 cents

we subtract this from the 10 cents we are playing with, thus we are left with 9-10 = -1 cent

7 0
2 years ago
Which equation can be used to find 75 percent of 200?
Shtirlitz [24]

Answer:

The first equation

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve the equation 3b1b-8=4​
joja [24]

Answer:

b = 2

Step-by-step explanation:

3b1b-8 = 4

       +8  +8

3b1b = 12

3b^2 = 12

/3          /3

b^2 = 4

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b = 2

6 0
3 years ago
Simplify the expression: (13 - 18) + 24 = 6
tresset_1 [31]
The answer is A. -7 1/3
4 0
2 years ago
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