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11111nata11111 [884]
4 years ago
10

What is the primed factored root for 12

Mathematics
1 answer:
Studentka2010 [4]4 years ago
8 0

Answer:

122 = 144

or

√12 = 3.464

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The number which occurs most frequently in a set of numbers is the ........?
Tpy6a [65]

Answer:

first

Step-by-step explanation:

it's the first number so

3 0
4 years ago
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Last season two running back's on the college football team rush for a combined 1550 yards one rushed four times as many yards a
dmitriy555 [2]

Answer:

The player with the most runs had a rush of 1,240 yards

Step-by-step explanation:

In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.

Firstly, let the person that had the smaller number of rush have a rush of x rushes. The second person has a rush of 4 times the other. This makes a number of 4x rushes

By adding both together, we have a total of 1550 yards

Mathematically, this means that x + 4x = 1550

5x = 1550

x = 1550/5 = 310 rushes

The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes

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4 years ago
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If x=7 and y=3 what is the value of x+5y<br><br> i need help
aksik [14]

If x=7 and y=3, then

x+5y=7+5(3)

5(3)=15

15+7=22

So x+5y=22

8 0
4 years ago
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Ronnie cut a piece if ply wood into 4 equal sections. the original length of the ply wood is 23.8 inches about how long is each
Blababa [14]

Answer:

5.95 inches

Step-by-step explanation:

So, the problem says that the piece of ply wood was cut into 4 equal sections and that the original length was 23.8 inches long. This is a simple equation. All you have to do is cut, or divide, 23.8 into 4 pieces. so 23.8 ÷ 4. So Ronnie cut the ply wood into 4 pieces that measure 5.95 inches each.

Hope I Helped!

4 0
3 years ago
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Lubov Fominskaja [6]

Answer:

CosC = \frac{3}{5}

Step-by-step explanation:

Cos C = \frac{Adjacent}{Hypotenuse}

<em>Where Adjacent = 24 , Hyp = 40</em>

Cos C = \frac{24}{40}

<u><em>In simplest form</em></u>

CosC = \frac{3}{5}

7 0
4 years ago
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