What is the primed factored root for 12

The equation for line A is y = -2/3 x -4. Line A and Line B are perpendicular and the point ( -2 , 1) lies on Line B. Write the

gavmur [86]

A23425

Step-by-step explanation:

5 0

2 years ago

Allan keeps tropical fish his aquarium is 4 feet long ,1 foot wideand 2 feet tall each fish needs atleast 0.5ft 3 of water what

Alik [6]

Answer: There are 16 fish that he can keep in the aquarium.

Step-by-step explanation:

Since we have given that

Length of aquarium = 4 feet

Width of aquarium = 1 foot

So, it forms a shape of cuboid.

As we know the formula for "Volume of Cuboid":

$Volume=Length\times Breadth\times Height\\\\Volume=4\times 1\times 2\\\\Volume=8\ ft^3$

According to question, Each fish needs atleast 0.5 cubic feet of water.

So, Number of fish that he can keep in the aquarium is given by

$\frac{8}{0.5}=16$

Hence, there are 16 fish that he can keep in the aquarium.

6 0

2 years ago

Evaluate ((6+2) ÷ (10-8) +10) ∙ 5

miskamm [114]

You can do that on photo math

5 0

3 years ago

Roberto wants to display his 18 sports cards in an album . Some pages hold 2 cards and others hold 3 cards .

nexus9112 [7]

Answer:

Step-by-step explanation:

Assuming Roberto wants to completely fill each page that he puts cards in, this function describes the number of 2-card pages, a, and 3-card pages, b.

2a + 3b =18

Ricardo can fill up 9 2-card pages, and 6 3-card pages.

a=9, b=0

We must add 2 3-card pages at a time,so that we have an even number for the 2-card pages:

a=6, b=2

Add 2 to b once more:

a=3, b=4

One more time:

a=0, b=6:

Thus, Ricardo can display his figures in the following page combinations:

a=9, b=0

a=6, b=2

a=3, b=4

a=0, b=6

Remember that a= number of 2-card pages and b=number of 3-card pages

There are 4 different ways that Ricardo can arrange his figures in terms of what kind of pages he uses.

3 0

3 years ago

If n+h/5=f+9/9, then n/5=

Ann [662]

------------------------------------------------------------------
Question
------------------------------------------------------------------
$\boxed { \frac{n+h}{5} = \frac{f+9}{9}}$

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
$\boxed { \frac{n}{5} + \frac{h}{5} = \frac{f + 9}{9}}$

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{f+9}{9} - \frac{h}{5}}$

------------------------------------------------------------------
Change the denominator to be the same
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}$

------------------------------------------------------------------
Put it into single fraction
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }$

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
$\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }$

$\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}$

6 0

3 years ago