Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,
Answer:
Step-by-step explanation:
Daddy chill
Hi STEP BRO AND STEP SIS WHAT ARE YALL DOING ON THIS APP
Answer:
$1,555.06
Step-by-step explanation:
I’m really sorry I just don’t know I guess I’m. It smart enough try to look it up and wait for someone else to answer sorry again :(
Answer:
D. 3 and 116
Step-by-step explanation:
d.f.N = k - 1 (numerator degrees of freedom) = 4 - 1 = 3
N = 4 × 30 = 120
d.f.D = N - k (denominator degrees of freedom) = 120 - 4 =116