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eimsori [14]
3 years ago
11

Solve for a.–13. 4a = 33.5

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0

Answer:

a=11.625

a=8.375

Step-by-step explanation:

The first answer is if the -13. means -13 multiplied by 4a and the second one is if 4a=33.5 without the -13.

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43. Find the equation of a line perpendicular to the y-axis passing through the point (4, 7).
iVinArrow [24]

9514 1404 393

Answer:

  y = 7

Step-by-step explanation:

The y-axis is the vertical line x=0. A perpendicular line will be a horizontal line that will have an equation of the form ...

  y = constant

In order for that line to go through a point with y-coordinate 7, the line must be ...

  y = 7

6 0
3 years ago
Slice the system of equations below 4×+y=16 and 2×+y=-2
BartSMP [9]
Answer: x = 9, y = -14

Explanation:

4x + y = 16 
2x + y = -2<span>

</span>   4x + y = 16 
-  2x + y = -2
-------------------
   2x + 0 = 18
-------------------

2x = 18
x = 9         <<<<<  ¯\_(ツ)_/¯ For the value of x

Plug x = 9 into  2x + y = -2

2(9) + y = -2
12 + y = -2
y = -14         <<<<<  ¯\_(ツ)_/¯ For the value of y

5 0
4 years ago
What is the solution to this equation: -5x + 4 = 29 *
Flauer [41]

\text{Hi there! :)}

Answer:

\huge\boxed{x = -5}

-5x + 4 = 29

\text{Subtract 4 from both sides:}

-5x + 4 - 4 = 29 - 4\\\\-5x = 25

\text{Divide both sides by -5:}

-5x / (-5) = 25 / (-5)\\\\x = -5

4 0
3 years ago
Read 2 more answers
In the year 2006, a person bought a new car for $18000. For each consecutive year after that, the value of the car depreciated b
Liula [17]

Answer:

Step-by-step explanation:

Use the exponential function

v(t)=a(b)^t where a is the initial value of the car, b is the rate of decay, and t is the time in years. For us, a = 18000, b = (1 - .15), so the model for this car is:

v(t)=18000(.85)^t  We can use this model now to find the value, v(t), of the car after 3 years has gone by (from 2006 to 2009 is 3 years):

v(t)=18000(.85)^3 and simplifying a bit:

v(t) = 18000(.614125) so

v(t) = 11054.25

Round however you need to.

5 0
3 years ago
Reuben drove 260 miles using 12 gallons of gas. At this rate, how many gallons of gas would he need to drive miles
KATRIN_1 [288]

Answer:

286 miles / x gallons = 15miles per gallon.

286/15 = x = approximately 19.07 gallons.

Step-by-step explanation:

8 0
3 years ago
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