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dangina [55]
3 years ago
13

HELP PLEASE 15PTS + BRAINLIEST

Mathematics
1 answer:
irakobra [83]3 years ago
6 0

Answer:


Number of points, x, Number of segments, y

x: 2, 3, 4, 5, ... N,. ...

y: 1, 3, 6, 10, ... (N-1)(N)/2, ...


Step-by-step explanation:

Adding Nth point, there are N-1 new segments,

and (sum over {i = 1 to N-1} of i) total segments. As Gauss knew when he was c.10 yo, the sum is (N-1)(N)/2.

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What is the value of x?
QveST [7]

Answer:

12

Step-by-step explanation:

The hypotenuse of a 45-45-90 triangle is equal to the length of a leg times \sqrt{2}

So, in your problem,

x = 6\sqrt{2} (\sqrt{2}

  = 6(2) = 12

4 0
3 years ago
Ed buys a vase for £24 and adds 25% onto the price before putting it into his shop window.
lianna [129]
After the 25% discount the vase would cost $18.00
7 0
3 years ago
You start driving west for 20 miles, turn left, and drive south for another 14 miles. At the end of driving, what is your straig
sdas [7]
By using these measurements and drawing out a triangle, you have two sides “a” and “b” and are trying to find “c”. using pythagorean theorem you can determine that “a^2 + b^2 = c^2”. plug in your distances (20 and 14) and you get 24.4 as your distance.
4 0
2 years ago
Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). A new versio
stich3 [128]

Answer:

12.92%

Step-by-step explanation:

Mean of the scores= u = 500

Standard deviation = \sigma = 10.6

We have to find what proportion of students scored more than 512 marks.

The distribution of scores in a test generally follows the Normal distribution. So we can assume that the distribution of MCAT scores is normally distributed about the mean.

Since, the distribution is normal, we can use the concept of z scores to find the proportion of students who scored above 512.

The formula for z scores is:

z=\frac{x-u}{\sigma}

So, z score for x = 512 will be:

z=\frac{512-500}{10.6}=1.13

Thus,

P(X > 512) is equivalent to P(z > 1.13)

So, the test scores of 512 is equivalent to a z score of 1.13. Using the z table we have to find the proportion of z scores being greater than 1.13, which comes out to be 0.1292

Since,

P(X > 512) = P(z > 1.13)

We can conclude that, the proportion of students taking the MCAT who had a score over 512 is 0.1292 or 12.92%

5 0
4 years ago
Three more than five times the number of dogs find the algebraic expression
tangare [24]
Answer:

5d + 5

..........
7 0
4 years ago
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