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Lemur [1.5K]
2 years ago
10

The veterinarlan told Sally that her cat needs to lose 5 pounds. A healthy weight loss for her cat would be about 1 pound every

2 weeks. To model this situation, she graphed the following line, where y represents the number of pounds left to lose and x represents time in weeks. The equation for this line is y= ___x +___. If she continues the line, she would see that it would take ___ weeks for her cat to lose 5 pounds​
Mathematics
2 answers:
tresset_1 [31]2 years ago
7 0

Answer:

it would take the adverage of 10 weeks for her to lose 5 pounds did that help?

Step-by-step explanation:

padilas [110]2 years ago
4 0

Answer:

It would take 10 weeks for her cat to lose 5 pounds.

Step-by-step explanation:

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3 years ago
It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 122 feet. A transportat
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Complete Question

The complete question is shown on the first uploaded image

Answer:

the null hypothesis is  H_o  :  \mu =  122

the alternative hypothesis is H_a  :  \mu \ne  122

The test statistics is  t =  - 1.761

The p-value is  p =  P(Z  <  t ) = 0.039119

so

    p  \ge 0.01

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu  = 122

     The sample size is  n=  38

    The sample mean is  \= x  =  116 \ feet

     The standard deviation is \sigma  =  21

     

Generally the null hypothesis is  H_o  :  \mu =  122

                the alternative hypothesis is H_a  :  \mu \ne  122

Generally the test statistics is mathematically evaluated as

         t =  \frac { \= x - \mu }{\frac{ \sigma }{ \sqrt{n} } }

substituting values

         t =  \frac { 116 -  122 }{\frac{ 21 }{ \sqrt{ 38} } }

         t =  - 1.761

The p-value is mathematically represented as

      p =  P(Z  <  t )

From the z- table  

     p =  P(Z  <  t ) = 0.039119

So  

     p  \ge 0.01

 

         

     

           

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