Let the integers be n, n+2 and n+4. We have "<span>sum of the least integer and the middle integer is 28 more than the greatest integer", so the </span>equation: n+(n+2)=28+(n+4) Solving the above equation for n: 2n-n=28+4-2 n=30. The three integers then are: 30, 32 and 34.
