Hello:<span>
the equation is : y = ax+b
the slope is a : a×(-3/2) = -1......(
perpendicular to a line with a slope of -3/2)
a = 2/3
y=(2/3)x+b
the line that passes through (-2, -2) : -2 =
(2/3)(-2)+b
b = -2/3
<span> the equation is : y = (2/3)x-2/3</span></span>
Answer:
(-3)^1+0
Step-by-step explanation:
Answer:
- |t -(-5)| = 1.5
- [-6.5, -3.5] = [minimum, maximum]
Step-by-step explanation:
The magnitude of the difference between the temperature (t) and -5 will be 1.5 at the limits:
|t -(-5)| = 1.5
This is equivalent to two equations:
In each case, the equation is solved by subtracting 5 from both sides:
- t = -6.5 . . . . minimum allowed temperature
- t = -3.5 . . . . maximum allowed temperature
Answer:
yes the answer is the answer that you need lol thx
hope it helped :)
Step-by-step explanation:
Solution:
Given that the point P lies 1/3 along the segment RS as shown below:
To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have
Using the section formula expressed as
![[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2C%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5D)
In this case,
where
Thus, by substitution, we have
![\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5B%5Cfrac%7B1%282%29%2B2%28-7%29%7D%7B1%2B2%7D%2C%5Cfrac%7B1%284%29%2B2%28-2%29%7D%7B1%2B2%7D%5D%20%5C%5C%20%5CRightarrow%5B%5Cfrac%7B2-14%7D%7B3%7D%2C%5Cfrac%7B4-4%7D%7B3%7D%5D%20%5C%5C%20%3D%5B-4%2C%5Ctext%7B%200%5Crbrack%7D%20%5Cend%7Bgathered%7D)
Hence, the y-coordinate of the point P is
