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dybincka [34]
3 years ago
14

RLY need help. dont understand PLEASE

Physics
1 answer:
Nookie1986 [14]3 years ago
4 0

Do you see the places in the question where it says all the things like ...

-- that YOU assembled

-- the voltage and resistance of each bulb

-- the measured total voltage and total current

-- the values that YOU calculated

-- use YOUR data

-- change in equivalent resistance, voltage drop across each bulb, and total voltage

These ALL refer to information that you were given before you started the exercise, or to measurements that you were supposed to measure.  So first of all, we don't have the information that was given to you before the exercise.  Regarding the measurements, either you measured them, or else you didn't measure them.  If you DID measure them, we need to know the measurements in order to answer the questions, because ALL of the questions are asking about those measurements.  If you DIDN't measure them, then the information we need to answer the questions <em>doesn't exist anywhere</em>, until somebody goes and measures them.  So, anybody who would like to just hand you a bunch of answers is totally stuck ... IF the answers even exist, we don't have ANY of the information needed to find them with.

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(A) We are using them faster than they are replenished by nature

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when a temparature of a coin is 75°C, the coin's diameter increases. if the original diameter of a coin is 1.8*10^-2 m and its c
andrey2020 [161]

Answer:

ΔD = 2.29 10⁻⁵ m

Explanation:

This is a problem of thermal expansion, if the temperature changes are not very large we can use the relation

          ΔA = 2α A ΔT

the area is

         A = π r² = π D² / 4

we substitute

         ΔA = 2α π D² ΔT/4

as they do not indicate the initial temperature, we assume that ΔT = 75ºC

    α = 1.7 10⁻⁵ ºC⁻¹

we calculate

          ΔA = 2 1.7 10⁻⁵ pi (1.8 10⁻²) ² 75/4

          ΔA = 6.49 10⁻⁷ m²

by definition

           ΔA = A_f- A₀

           A_f = ΔA + A₀

           A_f = 6.49 10⁻⁷ + π (1.8 10⁻²)² / 4

           A_f = 6.49 10⁻⁷ + 2.544 10⁻⁴

           A_f = 2,551 10⁻⁴ m²

the area is

           A_f = π D_f² / 4

           A_f = \sqrt{4  A_f /\pi }

           D_f = \sqrt{4 \ 2.551 10^{-4} /\pi }

           D_f = 1.80229 10⁻² m

the change in diameter is

           ΔD = D_f - D₀

           ΔD = (1.80229 - 1.8) 10⁻² m

           ΔD = 0.00229 10⁻² m

           ΔD = 2.29 10⁻⁵ m

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3 years ago
A sample of gas is enclosed in a container of fixed volume. Identify which of the following statements are true. Check all that
motikmotik

Answer:

B. If the container is cooled, the gas particles will lose kinetic energy and temperature will decrease.

C. If the gas particles move more quickly, they will collide more frequently with the walls of the container and pressure will increase.

E. If the gas particles move more quickly, they will collide with the walls of the container more often and with more force, and pressure will increase.

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4 years ago
What is matter? Give a grade 10/11/12 understanding.
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Matter can be many things, but is mostly made of atoms. Atoms are small things that cannot be seen directly, as lights either passes through it or alters it. However, we know that atoms are made of 3 parts, those being the proton, neutron, and electron.

Protons have a positive electromagnetic charge.

Neutrons have no charge.

Electrons have a negative charge equal to the protons positive charge.

Protons and neutrons make up what's called the nucleus, which is orbited by the electrons.

Protons and neutrons also share another thing in common, that being their composition.

Until relatively recently, we thought that these were the smallest particles in the universe, and indestructible. However, modern discoveries have revealed that they are actually made of quarks and gluons.

These are actually indestructible, being part of the group that is elementary particles.

3 0
4 years ago
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