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mezya [45]
2 years ago
12

A 400 g ball swings in a vertical cirde at the end of

Physics
1 answer:
velikii [3]2 years ago
8 0

Answer:

15.10m/s

Explanation:

The mass of the ball(m)=400g = 0.4kg

The radius of the string is(r)=15m

The tension in the string is(T)=10N

The acceleration due to gravity = 9.8m/s^{2}

The tension in the string when the body is at the bottom is given by

T=\frac{mv^{2} }{r}+mg

To find the speed of the ball, we make v the subject of the formula

Therefore, v=\sqrt\frac{r(T-mg}{m}

v= \sqrt\frac{15(10-0.4*9.8)}{0.4}

v=\sqrt\frac{91.2}{0.4} \\

v=\sqrt228 = 15.10 m/s

The speed of the ball = 15.10m/s

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