Question

A 400 g ball swings in a vertical cirde at the end of

Answer 1

Answer:

15.10m/s

Explanation:

The mass of the ball(m)=400g = 0.4kg

The radius of the string is(r)=15m

The tension in the string is(T)=10N

The acceleration due to gravity = $9.8m/s^{2}$

The tension in the string when the body is at the bottom is given by

$T=\frac{mv^{2} }{r}+mg$

To find the speed of the ball, we make v the subject of the formula

Therefore, $v=\sqrt\frac{r(T-mg}{m}$

$v= \sqrt\frac{15(10-0.4*9.8)}{0.4}$

$v=\sqrt\frac{91.2}{0.4}$

$v=\sqrt228 = 15.10 m/s$

The speed of the ball = 15.10m/s