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mezya [45]
2 years ago
12

A 400 g ball swings in a vertical cirde at the end of

Physics
1 answer:
velikii [3]2 years ago
8 0

Answer:

15.10m/s

Explanation:

The mass of the ball(m)=400g = 0.4kg

The radius of the string is(r)=15m

The tension in the string is(T)=10N

The acceleration due to gravity = 9.8m/s^{2}

The tension in the string when the body is at the bottom is given by

T=\frac{mv^{2} }{r}+mg

To find the speed of the ball, we make v the subject of the formula

Therefore, v=\sqrt\frac{r(T-mg}{m}

v= \sqrt\frac{15(10-0.4*9.8)}{0.4}

v=\sqrt\frac{91.2}{0.4} \\

v=\sqrt228 = 15.10 m/s

The speed of the ball = 15.10m/s

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4 0
3 years ago
A very long string (linear density 0.7 kg/m ) is stretched with a tension of 70 N . One end of the string oscillates up and down
rewona [7]

To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by

V = \sqrt{\frac{T}{\rho}}

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T = Tension

\rho = Linear density

Our data are given by

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Amplitude , A = 7 cm = 0.07 m

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V = \sqrt{\frac{T}{\rho}}

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3 0
3 years ago
2 Points
Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

:\implies  Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

:\implies  50 N = 10 kg × Acceleration

:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}

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3 years ago
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If they both are moving with the same speed and direction
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The longer you continue to listen, the more beats will be heard.

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7 0
3 years ago
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