The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
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Work done by the force experienced by the object</h3>
The magnitude of the work done by force experience by the object is calculated as follows;
W = f.d
where;
- F is the applied force (2xyi + 3yj), where x and y are in meters
- d is the displacement of the object = (a, b)
The work done by the force is determined from the dot product of the force and the displacement of the object.
F = (2xyi + 3yj).(a + b)
W = (2abi + 3bj).(ai + bj)
W = (2a²b + 3b²)J
Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
The complete question is below:
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
How much work does the force do?
Learn more about work done here: brainly.com/question/8119756
Answer:
245 m
Explanation:
v = at + v₀
50.0 m/s = a (9.8 s) + 0 m/s
a = 5.10 m/s²
x = x₀ + v₀ t + ½ at²
x = 0 m + (0 m/s) (9.8 s) + ½ (5.10 m/s²) (9.8 s)²
x = 245 m
Answer:
1. Increase Efficiency: Insulating the condensate or hot water return lines reduces heat loss from the water returning to the boiler. The hotter the water returning to the boiler is, the quicker it is to convert back to steam, which takes less energy to accomplish.
Explanation:
Answer:
My answer is when the ball is going it experience kinetic energy which is the energy of a moving object while when the ball has stopped then it will have potential energy which means it's at rest so for the ball not to experience friction then there is a gain in kinetic energy and decrease in potential energy.
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