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Sav [38]
4 years ago
8

F(y) = y2 +3 , at y = 2

Mathematics
1 answer:
laila [671]4 years ago
4 0

Answer:

f

Step-by-step explanation:

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How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
-BARSIC- [3]
The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

6 0
3 years ago
Simplify (√3 − √7)^2
Alika [10]

Answer: 10 - 2√21

Step-by-step explanation: I simplified your question by using an online calculator. :)

3 0
3 years ago
Question 1
Galina-37 [17]

Answer:

Did you find the answer???

5 0
3 years ago
The distance between Taylor’s house and her school is 300,000 centimeters.
Sergio [31]

Answer:

30 km

Step-by-step explanation:

1 kilometer = 100 meters.

1 meter = 100 cm

therefore, 1 km = 10,000

and then, 300000 cm is 30 km

7 0
4 years ago
A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes
bekas [8.4K]

Answer:  1) 1/3,654     2) 3/406     3) 72,684,900,288,000      4) 120

<u>Step-by-step explanation:</u>

1)         First       and        Second         and         Third

  \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}

2)         First       and          Second

   \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}

3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}

4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}

8 0
3 years ago
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