All categories

3 years ago

In a company, it takes 4 employees 4 days to complete a task. It would take 2 employees 8 days to complete the same task.

2 answers:

6 0

The concept that can be used in order to answer this item is that of man-days. The total number of man-days required to do the job should always be constant.

This can be illustrated by the givens above.
Scenario 1:
N1 = (4 employees)(4 days) = 16 man-days

Scenario 2:
N2 = (2 employees)(8 days) = 16 man-days

The equation for determining the value of e is equal to,
k = (d)(e)

The answer is the second choice.

Mariulka [41]3 years ago

4 0

Answer: inverse variation; $de = k$

Step-by-step explanation:

Given: In a company, it takes 4 employees 4 days to complete a task.

Work done by complete the task by = $4\times4=16$

Similarly, It would take 2 employees 8 days to complete the same task.

Work done by complete the task = $2\times8=16$

There is inverse variation which means if number of workers decreases then the number of days increases.

If e represents the number of employees working on the task and d represents the number of days it takes them to complete that task.

Then, by inverse variation $de = k$

You might be interested in

10-kg batch of a food product has a moisture content of175% dry basis. Calculate the amount of water to beremoved from the produ

sleet_krkn [62]

Answer:

4.9kg of water

Step-by-step explanation:

Dry basis is the percentage ratio of moisture amount to amount of dry product which is 175%

Ratio of moisture amount to dry product = 175 : 100

Mass of food product = 10kg

Amount of moisture in food product = 175/175+100 × 10kg = 175/275 × 10kg = 6.4kg

Wet basis is the percentage ratio of the moisture amount to the total weight of material which is 15%

Ratio of moisture amount to total weight of material is 15 : 100

Amount of moisture in food product = 15/100 × 10kg = 1.5kg

Amount of water contained in the final product = 1.5kg

Amount of other components in the food product = 10kg - 6.4kg = 3.6kg

Total amount = 1.5kg + 3.6kg = 5.1kg

% of water = 1.5kg/5.1kg × 100 = 29%

3 0

3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

Water is an example of a solvent true or false !<br> Hurry up and answer

lara [203]

Yes water is a solvent

4 0

3 years ago

Can you help me plssssss

photoshop1234 [79]

120 square centimeters i think?

8 0

3 years ago

Read 2 more answers

Ascending order 1/2 1/3 5/12 3/4

tekilochka [14]

Answer:

1/3, 5/12, 1/2, 3/4

Step-by-step explanation:

5 0

3 years ago