Step-by-step explanation:

Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u>
And we need to solve the equation using Substituting method . So on taking the first equation ,
<u>Put </u><u>this</u><u> </u><u>value</u><u> </u><u>in </u><u>(</u><u>ii)</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Put </u><u>this</u><u> </u><u>Value</u><u> </u><u>in </u><u>(</u><u>I)</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Hence</u><u> the</u><u> </u><u>Value</u><u> </u><u>of </u><u>x </u><u>is </u><u>2</u><u>1</u><u> </u><u>and </u><u>y </u><u>is </u><u>(</u><u>-</u><u>6</u><u>)</u><u> </u><u>.</u>
It wouldn't affect the mean or the median.
Answer:
u just 82 + 59% = 130.38
Step-by-step explanation: