All categories

3 years ago

One fourth multiplied by four

Mathematics

2 answers:

podryga [215]3 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{1}{4} \times 4 = 1$

ziro4ka [17]3 years ago

5 0

1/4 • 4 = 1

One fourth multiply by 4 is a whole number which is 1

You might be interested in

Esther starts at one corner of a square field and walks 90 feet along one side to another corner of the field. She turns 90° and

erma4kov [3.2K]

The three sides make a right triangle and you know the base (90) and the height (70)

A = 1/2 bh or 1/2 x (70)x (90)= 3150 ft²

3 0

3 years ago

If you save three pennies on January 1, six pennies on January 2, nine pennies on January 3, and continue this pattern for one y

lbvjy [14]

This is an arithmetic series with first term a1 = 3 and common difference = 3

Sum after 365 days = (365/2)[ 2*3 + (365-1)*3]

= 200,385 pennies = $2003.85 Answer

5 0

3 years ago

A store had a sale where you could get 7 bags of cashews for $2. If you wanted to buy 70 bags, how much would it cost?

expeople1 [14]

Answer:

$20

Step-by-step explanation:

7 x __=70

2 x ____=___

7 x 10 = 70

2 x 10

=20

6 0

2 years ago

Read 2 more answers

London bought a bag containing 95 small candies. She starts eating the

Savatey [412]

Answer: 19

Step-by-step explanation: let the number of candies left in the bag be y and the number of minutes eating be x.

Because she eats 5 candies per minute

8 0

2 years ago

Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.

Nuetrik [128]

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

$(x-r_{i})^{m},\,m \le n$ (1)

Where $n$ is the grade of the polynomial.

Now we proceed to factor the formula:

$y = x^{5}-27\cdot x^{2}$

$y = x^{2}\cdot (x^{3}-27)$

$y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)$

Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

$y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3} \right)\cdot (x-3)$

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0

2 years ago