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zimovet [89]
4 years ago
8

Solve by elimination x-5y=35 and 3x-6y=51

Mathematics
2 answers:
S_A_V [24]4 years ago
7 0

Answer:

x=5

y= -6

Step-by-step explanation:

equ= equation

x - 5y= 35 ----- equ (1)

3x - 6y= 51 ----- equ (2)

Multiply equ (1) by 3

3x - 15y= 105 ----- equ(3)

3x - 6y= 51 ----- equ(4)

Subtract equ(4) from equ(3)

-9y= 54

y= -6

Substitute value of y into equ(1)

x - 5 x -6= 35 (the second x here means multiplication)

x + 30= 35

x= 5

IrinaVladis [17]4 years ago
3 0

Answer: x=5 y=-6

(5,-6)

Step-by-step explanation:

Solve by elimination

\begin{bmatrix}x-5y=35\\ 3x-6y=51\end{bmatrix}

multiply x-5y=35 by 3

= 3x-15y=105

\begin{bmatrix}3x-15y=105\\ 3x-6y=51\end{bmatrix}

3x-6y=51

-\underline{3x-15y=105}

9y=-54

divide 9 on both sides

y= -6

Now solve for x

you must plug in -6 for y in either equations

i plugged in -6 for y in 3x-15y=105

3x-15\left(-6\right)=105

3x+15\cdot \:6=105

15\cdot \:6=90

3x+90=105

subtract 90 on both sides

3x=15

\frac{3x}{3}=\frac{15}{3}

x=5

Please mark brainliest

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