If two secants intersect from a point outside of the circle, then the product of the lengths of the secant and its external segment equals the product of the other secant and its external segment.
#1
5(x+5) = 6(4+6)
5x + 25 = 6 * 10
5x = 60 - 25
5x = 35
x = 7
#2
4(x+4) = 3(5+3)
4x + 16 = 3 * 8
4x = 24 - 16
4x = 8
x = 8/4
x = 2
Answer:
<h2>x³ + 8x² - 3x - 24 = (x + 8)(x - √3)(x + √3)</h2>
Step-by-step explanation:
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
5^2 -7•4+(36-2^(5) so do (36-2^5 first put that in the calculator which gets u 32.Then bring down 5^2-7•4+32 then do 5^2 and 7×4 which 25 -28+32 add them together u get 60 so 25 -60 is 35
