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3 years ago

Completely Factor the following equations. a) 3x^3 + 15x^2 + 18x

1 answer:

3 0

Common factor
3x^3 + 15x^2 + 18x

3(x^3+5x^2+6x)
Find one factor
3x(x^2+5x+6)
Factor by grouping
3x(x+2)(x+3)
Solution
3x(x+2)(x+3)

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Determine the root of the equation

larisa [96]

Answer:

0.97087

Step-by-step explanation:

Given the function:

$f(x) = e^{2x} - x - 6$

Its first derivative is:

$f'(x) = 2e^{2x} - 1$

Using Newton's method:

$x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}$

and starting with the point:

$x_1 = 0.95$

we get:

$f(x_1) = e^{2(0.95)} - 0.95 - 6 = -0.26410$

$f'(x_1) = 2e^{2(0.95)} - 1 = 12.37178$

$x_2 = x_1 - \frac{f(x_1)}{f'(x_1} = 0.95 - \frac{-0.26410}{12.37178} = 0.97134$

$f(x_2) = e^{2(0.97134)}- 0.97134 - 6 = 0.00608$

$f'(x_2) = 2e^{2(0.97134)} - 1 = 12.95485$

$x_3 = 0.97134 - \frac{0.00608}{12.95485} = 0.97087$

$f(x_3) = e^{2(0.97087)} - 0.97087 - 6 = -2.6240413 \cdot 10^{-7}$

6 0

3 years ago

Kory bought 2 boxes of candy and 1 soda at the movies and paid $8.00.christopher bought 1 box of candy and 1 soda and paid $5.50

viva [34]

Let c represent candy and s soda.
2c+s=8
c+s=5.5
Solving the pair of simultaneous equations by eliminating s,
c=2.5
Representing the value of c in equation 1;
5+s=8
s=3
So, a box of Candy costs 2.5 and a soda costs 3

4 0

3 years ago

PLEASE HELP DEW IN 1 hour

Marta_Voda [28]

Answer: B

Step-by-step explanation:

2(—2) + 10 = 6.

2(0) + 6 = 6.

2(2) + 2 = 6.

2(4) + (—2) = 6

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3 years ago

1/2-(-1/3)<br><br> Does anyone know the answer to this question?

Alexxx [7]

Answer:

5/6

.......................

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3 years ago

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Find f^-1(x) for f(x)=1/x^3

Nata [24]

if you love god give me 5 stars.................

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3 years ago