Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
First multiple of 4 is x = 144
Second multiple of 4 is x + 4 = 144 + 4 = 148
Third multiple of 4 is x + 8 = 144 + 8 = 152
Answer:
y=5x-3
Step-by-step explanation:
y=mx+b where m=slope and b= y-intercept
Answer:
c. x = -1/15
Step-by-step explanation:
5/2x - 1/3 = -1/2 [multiply the whole equation by 6 (lowest common denom)
15x - 2 = -3 [add 2 on both sides of equation
15x = -1 [divide both sides by 15 to isolate x]
x = -1/15
Check attached file for solution.
