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Simora [160]
3 years ago
15

Jerry spent 2/3 of his money on a gift for his brother and 1/12 of the money on a card. He saved ther rest. What fractional amou

nt of money did Jerry save?
Mathematics
1 answer:
____ [38]3 years ago
4 0
1 - 2/3 - 1/12 = 3/12 reduced = 1/4

Jerry saved 1/4 of his money.
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o-na [289]
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3 0
3 years ago
Name 4 pairs of corresponding angles
SOVA2 [1]

Answer:

1.  Alternate angles, 2. Right angle, 3. Acute Angle, 4. Reflex angle

Step-by-step explanation:

5 0
3 years ago
Please help I need it today please help
Rufina [12.5K]
0-2+9=7 is the answer I think
6 0
3 years ago
Prove that <br><img src="https://tex.z-dn.net/?f=4cot45%20%5E%7B2%7D%20%20-%203tan%20%5E%7B2%7D%2060%20%2B%202sec%20%5E%7B2%7D60
sesenic [268]

Answer:

4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  = 3 \\

LHS = 4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  \\

let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.

here ,

\cot(45)  = 1 \\  \\  \tan(60)  =  \sqrt{3}  \\  \\  \sec(60)  = 2

now ,

we just have to plug in the values considering certain other things given in the question and we're done!

so let's start ~

4(1) {}^{2}  - 3( \sqrt{3} ) {}^{2}  + 2(2) {}^{2}  \\ \\ \dashrightarrow \: 4(1) - 3(3) + 2(4) \\ \\ \dashrightarrow \: 4 - 9 + 8 \\\\ \dashrightarrow \: 12 - 9 \\ \\\dashrightarrow \: 3 = RHS

hence , proved ~

hope helpful :D

7 0
2 years ago
The length of a photograph is 1 less than twice the width. The area is 45 cm squared. Find the dimensions of the photograph.
kkurt [141]

the lenght is 9 and the width is 5 so 9 by 5

7 0
3 years ago
Read 2 more answers
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