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4 years ago

How are the decimals 0.009 and 0.09 related? Explain

1 answer:

7 0

Considering the place value of the digit 9, in the first number, the decimal value of 9 is thousands. In the second number, the decimal value of 9 is hundredths. The conclusion we are drawing is: The second decimal is 10 times larger than the first one

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The Cooper family and the Reynolds family took a

kiruha [24]

Answer: well 2/3 of 1650 is 1100 so 1650-1100=550, so the cooper family spend $1100 and the reynolds family spent $550

Step-by-step explanation: i think that’s right

5 0

3 years ago

Terri is trying to save $250 so she can buy a new surfboard . She has \$75 saved already and plans to save $45 per week . How ma

kodGreya [7K]

Answer:

It will take Terri 4 weeks to save up enough money for a new surfboard.

Step-by-step explanation:

250-75= 175

175/45= 3.888

But its asking for whole weeks, so round to the nearest whole number, which is 4.

btw 45x4= 180 so she'll have 5 extra dollars.

8 0

3 years ago

Read 2 more answers

Find two different fractions whose sum is equal to 1

Veseljchak [2.6K]

1/2+1/2=1
2/4+2/4=1
Hope i helped:)

7 0

4 years ago

Read 2 more answers

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$