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Bumek [7]
3 years ago
6

Let R(x) =X-3/x-4. Solve for R(x) <= 0.

Mathematics
1 answer:
dezoksy [38]3 years ago
5 0

The value of x in the function is 3

Data;

  • R(x) = x-3/x-4
  • R(x) = 0
<h3>What is a Function?</h3>

A function from a set A to a set B assigns to each element of A exactly one element of B. The set A is usually the domain of the function while the set B is the codomain of the function.

Given that the function R(x) is

R(x) = \frac{x-3}{x-4}

And also, R(x) is equal to 0.

R(x) = \frac{x-3}{x-4}\\ 0= \frac{x-3}{x-4} \\0(x-4) = x - 3\\0 = x- 3\\x = 3

The value of x in the function is 3

Learn more on functions here;

brainly.com/question/1214333

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Use compatible numbers to estimate the quotient .179/9
Alisiya [41]

Answer:

179 divided by 9 is approximately 19.88. Rounded to the nearest tenth, it is 19.9.

Step-by-step explanation:

Since the .8 in 19.88 is above the number 5, the number will get rounded to a higher number ( 9).

4 0
3 years ago
Read 2 more answers
The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.
Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or​ less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 ​seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}

The probability for exponential distribution is given as:

P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}

a) P( time between the next two calls will be 54 seconds or​ less)

P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763

0.52763 is the probability that the time between the next two calls will be 54 seconds or​ less.

b) P(time between the next two calls will be greater than 118.5 ​seconds)

p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285

0.19285 is the probability that the time between the next two calls will be greater than 118.5 ​seconds.

6 0
4 years ago
A hemispherical tank is filled with water and has a diameter of 14 feet. If water
tigry1 [53]

Answer:

44,826.72\ \text{pounds}

Step-by-step explanation:

Given that,

The diameter of a hemispherical tank= 14 feet

Radius, r = 7 feet

water

Water weighs 62.4 pounds per cubic foot.

We need to find the total weight of the water in a full tank to the nearest pound.

The volume of the hemisphere is given by :

V=\dfrac{2}{3}\pi r^3\\\\V=\dfrac{2}{3}\pi \times (7)^3\\\\V=718.377\ \text{feet}^3

If water weighs 62.4 pounds per cubic foot, it means

V=718.377\times 62.4\\\\V=44,826.72\ \text{pounds}

So, the total weight of the water is 44,826.72\ \text{pounds}.

3 0
3 years ago
Plot the image of point C under a dilation about the origin (0,0) with a scale factor of 1/2
yuradex [85]

Answer:

See Attachment for graph

Step-by-step explanation:

Given

Point C

Required

Plot C when dilated by 1/2

First, we have to determine the coordinates of point C

From the attached graph;

C = (0,6)

Next, is to determine the new point when dilated;

This is calculated as thus;

New\ Point = Old\ Point * Scale\ Factor

C' = (0,6) * \frac{1}{2}

Expand the bracket

C' = (0 * \frac{1}{2}, 6* \frac{1}{2})

C' = (0, \frac{6}{2})

C' = (0, 3)

This implies that C' will be plotted at x =0 and y = 3

<em>(See attached for point C')</em>

6 0
4 years ago
Solve for the value of p​
sergeinik [125]

Answer:

43°

Step-by-step explanation:

p + 7° + 3p+ 1° = 180° ( Being linear pair)

4p + 8° = 180°

4p = 180° - 8 °

4p = 172°

p = 172° / 4

p = 43°

Hope it will help :)❤

4 0
3 years ago
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