Question

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 9 feet and a height of 18 feet. Container B has a radius of 11 feet and a height of 17 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. After the pumping is complete, what is the volume of the empty portion of Container B, to the nearest tenth of a cubic foot?

Answer 1

Answer:

Answer:

To find the volume of a cylinder, use the equation  where  represents volume,  represents radius, and  represents height.

Find the volume of both cylinder containers.

Container A:

Container B:

Now, subtract the volume of Container A from Container B and find the difference. The difference will be the volume of the empty portion of Container B.

Lastly, round the difference to the nearest tenth of a cubic foot.

Answer 2

Answer:

$1881.8 ft^{3}$

Step-by-step explanation:

To find the volume of a cylinder, use the equation $V = \pi r^{2} h$ where $V$ represents volume, $r$ represents radius, and $h$ represents height.

Find the volume of both cylinder containers.

Container A:

$V = \pi (9)^{2} (18)$

$V = 4580.442089$ $ft^{3}$

Container B:

$V = \pi (11)^{2} (17)$

$V = 6462.256088$ $ft^{3}$

Now, subtract the volume of Container A from Container B and find the difference. The difference will be the volume of the empty portion of Container B.

$6462.256088 - 4580.442089 = 1881.813999$ $ft^{3}$

Lastly, round the difference to the nearest tenth of a cubic foot.

$1881.8 ft^{3}$