Answer:
S = 128πx² + 64πx + 8π
Step-by-step explanation:
Suraface area of a cylinder is given by:
S = 2πrh + 2πr²
We know that the height is 3 times as big as the radius, hence:
h = 3r
so we can plug in the new h value and rewrite the S equation as:
S = 2πrh + 2πr²
S = 2πr(3r) + 2πr²
S = 6πr² + 2πr²
S = 8πr²
We're given in the question that the radius is (4x + 1) inches, so plug that into r.
Given: r = 4x + 1
Therefore,
S = 8πr²
S = 8π(4x + 1)²
S = 8π(16x²+8x+1)
S = 128πx² + 64πx + 8π
Answer:
Twenty-one times the quantity of a+8.
The formula for a circumference of a circle is 2πr
2 × π × 25 = 157
so your answer is A 157in.
I hope I've helped!
X/8 - 10 = x/3
bring the values with the variable on one side
x/3 - x/8 = 10
find a common denominator and subtract these fractions
8x/24 - 3x/24 = -10
now subtract fractions
8x - 3x = 5x
5x/24 = -10
multiply both sides by 24
5x = -240
divide both sides by 5
x = -48
the number is -48