What factors should be considered when deciding whether or not to purchase whole life insurance?

A library is buying books at a constant rate of 150 books per year. The equation

zloy xaker [14]

Answer:

C

Step-by-step explanation:

The answer is C, because X is per year, so its 150 books per year, and the library already had is 7000 bc your adding that number to the amount of books your going to buy per year

7 0

3 years ago

Read 2 more answers

Jen and Ron each took five tests. Their test scores are shown below.

Molodets [167]

The statement that correctly compares the students’ test scores is that the median of Jen's score is greater than the median of Ron's score.

<h3>How to find mean and median?</h3>

Jen and Ron each took five tests. There test score are as follow:

Jen: {45, 91, 84, 66, 74}
Ron: {70, 95, 99, 69, 72}

Let's find the mean and median of the test score to compare them correctly

Jen: {45, 66, 74, 84, 91}

mean of Jen score = 45 + 66 + 74 + 84 + 91 / 5

mean of Jen score= 360 / 5

mean of Jen score = 72

Median of Jen score = 74

Ron: {69, 70, 72, 95, 99}

mean of Ron score = 69 + 70 + 72 + 95 + 99 / 5

mean of Ron score = 405 / 5

mean of Ron score = 81

median of Ron score = 72

Therefore, the median of Jen's score is greater than the median of Ron's score.

learn more on mean and median here: brainly.com/question/27388918

#SPJ1

7 0

2 years ago

NO LINKS!!! Please help me with these problems

nadezda [96]

<h3>Answers:</h3>

7) Center= (-1,2) Radius= $\boldsymbol{\sqrt{8}}$ Equation: $(x+1)^2+(y-2)^2 = 8$

8) Center= (3,13) Radius= 13 Equation: $(x-3)^2+(y-13)^2 = 169$

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Explanation:

Problem 7

Let's find the distance from (-1,2) to (-3,4)

$(x_1,y_1) = (-1,2) \text{ and } (x_2, y_2) = (-3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-3))^2 + (2-4)^2}\\\\d = \sqrt{(-1+3)^2 + (2-4)^2}\\\\d = \sqrt{(2)^2 + (-2)^2}\\\\d = \sqrt{4 + 4}\\\\d = \sqrt{8}\\\\$

This is the radius because it stretches from the center to a point on the circle, so $r = \sqrt{8}$

Squaring both sides will get us $r^2 = 8$

One useful template for a circle is the equation $(x-h)^2+(y-k)^2 = r^2\\\\$

(h,k) is the center

r is the radius

Let's plug in the given center (h,k) = (-1,2) and the r^2 value we found earlier.

$(x-h)^2+(y-k)^2 = r^2\\\\(x-(-1))^2+(y-2)^2 = 8\\\\(x+1)^2+(y-2)^2 = 8\\\\$

You can confirm this by using a tool like Desmos. See below.

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Problem 8

The endpoints of the diameter are (-2,1) and (8,25)

The center is the midpoint of these endpoints.

The midpoint of the x coordinates is (-2+8)/2 = 3

The midpoint of the y coordinates is (1+25)/2 = 13

The center is (h,k) = (3,13)

Now find the distance from the center to one of the points on the circle, let's say to (8,25)

$(x_1,y_1) = (3,13) \text{ and } (x_2, y_2) = (8,25)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-8)^2 + (13-25)^2}\\\\d = \sqrt{(-5)^2 + (-12)^2}\\\\d = \sqrt{25 + 144}\\\\d = \sqrt{169}\\\\d = 13\\\\$