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3 years ago

12

One supplier quoted select 1 x 6 pine at $955M. Another quoted $0.65 per linear foot. Which one is less expensive; how much less

?

1 answer:

MrRa [10]3 years ago

6 0

0.65 per linear foot

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***I NEED HELP ASAP*** <br> ***Please show all the steps***<br> ***I will mark brainliest***

mixer [17]

Answer:

First on is 0.75

Second is 22/52 (not sure about this one though)

Step-by-step explanation:

For the first one:

P(aUb) = p(a) + p(b) - p(a^b)

0.6 = 0.4 + 0.5 - p(a^b)

p(a^b) = 0.3

P(a/b)= p(a^b)/p(a)

P(a/b)= 0.3/0.4

P(a/b)= 0.75

For the second one:

Total of the cards are 52

Diamonds are 13 out of that 52

Face cards are 12 out of that 52

Diamond OR face cards means p(aUb)

And that equals p(a)+p(b)-p(a^b)

p(a^b) means the intersection between the two, there are three common cards between diamonds and face cards, so p(a^b)=3

13/52 + 12/52 - 3/52= 22/52

3 0

3 years ago

Does somebody know how to find area of a trapizoid???

motikmotik

Answer:

To find the area of a trapezoid, multiply the sum of the bases (the parallel sides) by the height (the perpendicular distance between the bases), and then divide by 2.

Step-by-step explanation:

:) Hope this helps you with what you're working on!

5 0

2 years ago

Read 2 more answers

Help me plssssssss this is a math question

Flura [38]

“My neighbor owns his own property” your book said non mathematical, but tell me if it’s supposed to be. I can write you a new one.

8 0

3 years ago

Help me please, its due at night today!!!

postnew [5]

Answer:

Step-by-step explanation:

Area of polygon = area of square + area of triangle

Square:

Side = 12 cm

Area of square = side *side

= 12 * 12

= 144 sq.cm

Triangle:

base (b) = 12 cm

Height h = 19 cm

$Area =\frac{1}{2}bh\\\\=\frac{1}{2}*12*19\\$

= 6 * 19

= 114 sq.cm

Area of polygon = 144 + 114 = 258 square cm

4 0

3 years ago

Construct the discrete probability distribution for the random variable described. Express the probabilities as simplified fract

lisov135 [29]

Answer:

$P(X = 0) = 0.03125$

$P(X = 1) = 0.15625$

$P(X = 2) = 0.3125$

$P(X = 3) = 0.3125$

$P(X = 4) = 0.15625$

$P(X = 5) = 0.03125$

Step-by-step explanation:

For each toss, there are only two possible outcomes. Either it is tails, or it is not. The probability of a toss resulting in tails is independent of any other toss, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Fair coin:

Equally as likely to be heads or tails, so $p = 0.5$

5 tosses:

This means that $n = 5$

Probability distribution:

Probability of each outcome, so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125$

$P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625$

$P(X = 2) = C_{5,2}.(0.5)^{2}.(0.5)^{3} = 0.3125$

$P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125$

$P(X = 4) = C_{5,4}.(0.5)^{4}.(0.5)^{1} = 0.15625$

$P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125$

5 0

2 years ago