PLEASE HELP ME FOR 15 POINTS AND BRAINLIEST QUICK! thanks.
2 answers:
Answers:
Cumulative frequencies from top to bottom:
- 1
- 8
- 25
- 45
- 58
- 62
Other answers:
- There are <u>62</u> golfers total
- mode = 72
- Median is between slots <u> 31 </u> and <u> 32 </u>
- Median = 72
Refer to the diagram below
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Explanation:
In the first row, the frequency is 1, so that's the cumulative frequency for that row. It's the total frequency so far.
In the second row, the cumulative frequency is now 8 because we add the two frequencies so far (1+7 = 8)
The third row will have a cumulative frequency of 1+7+17 = 25.
The rest of the rows will follow this pattern to fill out the table. Refer to the diagram below to see the filled out table.
----------------------------
At the very end, you should get 62 golfers total (the cumulative frequency for the bottom row).
The mode score is the most frequent value. In this case, that's the score 72 since it shows up the most times (ie has the largest frequency).
Because we have n = 62 people total, the median is between slots n/2 = 62/2 = 31 and 32
Go back to the table and note how 25 is the cumulative frequency for the third row. Since 25 is smaller than 31 and 32, this means that the median cannot be in the first three rows. Instead, it's in the fourth row because the frequency 17 here is more than enough to get us from slot 25 to slots 31 and 32.
In other words, the values 72 and 72 are in slots 31 and 32. The midpoint of which is 72.
The median is therefore 72.
Side note: the mode and median aren't always the same value.
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Answer:
Bouquets of roses = 20
Bouquets of carnations = 08
Step-by-step explanation:
Let,
x be the bouquets of roses sold
y be the bouquets of carnations sold
According to given statement;
x + y = 28 Eqn 1
16x + 10y = 400 Eqn 2
Multiplying Eqn 1 by 16
16(x+y=28)
16x + 16y = 448 Eqn 3
Subtracting Eqn 2 from Eqn 3
(16x+16y)-(16x+10y) = 448 - 400
16x + 16y - 16x - 10y = 48
6y = 48
Dividing both sides by 6
Putting y=8 in Eqn 1
x + 8 = 28
x = 28 - 8
x= 20
Hence,
Bouquets of roses = 20
Bouquets of carnations = 08
Answer:
a) The expression for the height, 'H', of the plant after 't' day is;
b) The height of the plant after 30 days is approximately 19.426 inches
Step-by-step explanation:
The given maximum theoretical height of the plant = 30 in.
The height of the plant at the beginning of the experiment = 5 in.
a) The logistic differential equation can be written as follows;
Using the solution for the logistic differential equation, we get;
Where;
A = The condition of height at the beginning of the experiment
M = The maximum height = 30 in.
Therefore, we get;
A = 5
When t = 20, H = 12
We get;
∴ -(30·k)·20 = ㏑(1.5)
k = ㏑(1.5)/(30 × 20) ≈ 6·7577518 × 10⁻⁴
k ≈ 6·7577518 × 10⁻⁴
Therefore, the expression for the height, 'H', of the plant after 't' day is given as follows
b) The height of the plant after 30 days is given as follows
At t = 30, we have;
The height of the plant after 30 days, H ≈ 19.426 in.