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goldenfox [79]
3 years ago
7

A six sided number cube is rolled . find the probability of rolling a 3 or a number greater than 4.

Mathematics
2 answers:
Sindrei [870]3 years ago
5 0
The answer is c. 1/2
Kazeer [188]3 years ago
4 0
C 1/2 is the answer to that
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Answer:

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Find the area of the sector with a central angle of 120° and a radius of 8 inches. Leave in terms of π. A) 8 3 π in2 B) 16 3 π i
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Kendra charges $11 to shovel a driveway. She shoveled 4 driveways on Saturday and then some more on Sunday. She made $143 for th
White raven [17]

Let number of driveways , she shoveled on Sunday = x

And for 4 driveways , Kendra charges = 4*11=44

Therefore,

143 = 44 + 11x

And that's the model for the given situation .

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143-44 = 11x

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Therefore she shoveled 9 driveways on Sunday .

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What transformation has changed the parent function f(x) = 3(2)x to its new appearance shown in the graph below?
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Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
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