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My name is Ann [436]

3 years ago

13

What is f(5) for the function f? f(x) = 2(x - 7)

2 answers:

Elza [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Plug the 5 into the x's place F(5) = 2(5-7) 5-7 = -2 2 * -2 = -4

Romashka-Z-Leto [24]3 years ago

4 0

Step-by-step explanation:

f(5) = 2(5 - 7) = 2(-2) = -4.

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Solve the given equation<br> 16 - 5(3w - 4) = 8(-2w + 11)

KIM [24]

Answer:

16-15w+20=-16w+88

-15w+16w=88-16-20

w=52

5 0

3 years ago

Work out the missing value in the calculation below

fiasKO [112]

Answer:

5

Step-by-step explanation:

$\frac{2}{3} +\frac{1}{6}= \frac{ }{6} \\$

Here LCM will be 6. (We made the denominator same)

so, now the equation will be :

$\frac{2}{3}+\frac{1}{6} \\\\ =\frac{4}{6} + \frac{1}{6}$

= 5/6

So, the value in the red box is 5.

Hope it helps!

3 0

2 years ago

The width of the rectangle is 10 cm more than the length. The

alexira [117]

Answer:

The width is 35 cm.

The length is 25 cm.

Step-by-step explanation:

6 0

3 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago

The graphs of the equation y = 4x + 1 and y - kx = 10 are perpendicular when k = _______?

Ann [662]

Answer:

$k=-\frac{1}{4}$

Step-by-step explanation:

we have

Line 1

$y=4x+1$

Equation in slope intercept form

The slope is equal to

$m_1=4$

Line 2

$y-kx=10$

$y=kx+10$

Equation in slope intercept form

The slope is equal to

$m_2=k$

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)

so

$m_1*m_2=-1$

substitute

$(4)(k)=-1$

$k=-\frac{1}{4}$

3 0

3 years ago