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GREYUIT [131]
3 years ago
15

Use the box-and-whisker plots to find the interquartile range for both class B and class A?

Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0
Class a - 10
Class b - 15
Sladkaya [172]3 years ago
7 0

Answer:

class a- 10

class b- 15

Step-by-step explanation:

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Using the binomial theorem, expand the expression (4 + y) to the power of 4
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Answer:

When raised to the power of 4, the binomial (4 + y) expands to:

y^4 + 16y^3 + 96y^2 + 256y + 256

Step-by-step explanation:

(4 + y)^4 \\= (y^2 + 8y + 16)^2\\= y^4 + 8y^3 + 16y^2 + 8y^3 + 64y^2 + 128y + 16y^2 + 128y + 256\\= y^4 + 16y^3 + 96y^2 + 256y + 256

8 0
3 years ago
Having trouble with this one can somebody help?
Varvara68 [4.7K]
Form equation
y = mx + c
y = (rise/run).x + c
y = (11-1 / 3--2)x + c
y = 2x + c
11 = 2(3) + c
Find c (y-intercept)
11 - 6 = c
c = 5
Final equation of line
y = 2x + 5
Substitute given possible x-values in to find y-values
y = 2(1) + 5 = 7 (1,7)
y = 2(2) + 5 = 9 (2,9)
Therefore d is correct
3 0
3 years ago
2.
S_A_V [24]

B)

The corect answer for this question

6 0
2 years ago
What is the circumference of the circle with radius 8cm in terms of ?
Verizon [17]

Answer:

Step-by-step explanation:

C = 2\pi *r\\r = 8cm\\C = 2*\pi*8\\C = 16 \pi cm

6 0
3 years ago
Read 2 more answers
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of t
PIT_PIT [208]
The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.

Ways of having 17:

Die 1     Die 2     Die 3    sum
6            6            5          6+6+5 = 17
6            5            6          6+5+6 = 17
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Those are the only 3 possibilities of having 17 (you can only loose 1 point).

The total number of outcomes are 6*6*6 = 216

So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139 
8 0
3 years ago
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