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2 years ago

8.54 as a place value

Mathematics

1 answer:

alexandr402 [8]2 years ago

7 0

Eight and fifty four hundredths

8 . 5 4
Ones Tenths Hundredths

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Real estate ads suggest that 56 % of homes for sale have garages, 27 % have swimming pools, and 16 % have both features. a) W

Marizza181 [45]

Answer:

a) 0.4

b) 0.28

c) The events are not independent

d) The events are not mutually exclusive

Step-by-step explanation:

Hi!

Lets call:

Gar = {homes with garage}

Pool = {homes with pool},

A = {homes with pool and garage} = Gar ∩ Pool

The data we are given is:

P(Gar) = 0.56

P(Pool) = 0.27

P(A) = 0.16

a) B = {homes with garage but not pool}. This set B is the set Gar without set A: B = Gar / A

P(B) = P(Gar) - P(A) = 0.4

b) This is a conditional probability:

P(Pool | Gar) = P(Gar ∩ Pool) / P(Gar) = 0.16/0.56 = 0.28

c) To be independent events, it must be, by definition:

P(Gar ∩ Pool) = P(Gar) * P(Pool)

0.16 ≠ 0.56*0.27 = 0.15

Then, the events Gar and Pool are not independent

d) Gar and Pool are not mutually exclusive, because there are houses with both pool and garage. We know that because P(A) is not zero.

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3 years ago

What is the best metric unit to measure this item?<br><br> A small glass of milk

EastWind [94]

They are usually measured with milliliters; although, a half liter of milk is perfectly viable.

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3 years ago

Describe how the graph of y=|x| and how it is difficult

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Y= to the absolute function of x?
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3 years ago

Gil aunt cut his birthday cake into 32 equal pieces. eighteen pieces were eaten at his birthday party.what fraction of the cake

klasskru [66]

Started out with 32/32. They ate 18/32, 32-18=14; 14/32. To simplify, 7/16 was left.

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2 years ago

In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who p

Flauer [41]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

Given: There are 2 classes of 25 students.

13 play basketball

11 play baseball.

4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)= $\frac{13}{25} +\frac{11}{25} -\frac{4}{25}$

taking LCD as 25 to solve.

⇒P(a∪b)= $\frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}$

∴ P(a∪b)= $\frac{4}{5}$

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is $\frac{4}{5}$ .

6 0

3 years ago