Consider circle O. If AE = 7, EC = 2, and BE = 4, what is ED?
2 answers:
The correct answer is 3.5
Two chords AC and BD are intersecting inside the circle. The Intersecting Chord Theorem states that when two chords intersect inside a circle, the products of their segments are equal.
Thus, for the given circle:
(AE) × (EC) = (BE) × (ED)
The lengths of the segments are
AE = 7
EC = 2
BE = 4
ED = ?
To solve for ED, we simply substitute the known values into the equation
Two chords AC and BD are intersecting inside the circle. The Intersecting Chord Theorem states that when two chords intersect inside a circle, the products of their segments are equal.
Thus, for the given circle:
(AE) × (EC) = (BE) × (ED)
The lengths of the segments are
AE = 7
EC = 2
BE = 4
ED = ?
To solve for ED, we simply substitute the known values into the equation
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Answer:
C) 15
Step-by-step explanation:
Here we have to use the combination to find the number of possible combinations.
Total number of classmates (n) = 6
We are selecting 2 individuals. So r = 2.
The combination formula nCr =
Plug in n = 6 and r =2, in the above formula, we get
=
=
Simplifying the above factorial, we get
= 15
So the answer is C) 15
