Question

The endpoints of EF are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of EF?

Answer 1

Answer:

The coordinates of the midpoint of EF is equal to

$(\frac{xE+xF}{2},\frac{yE+yF}{2})$

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

In this problem we have

$(x1,y1)=(xE,yE)$

$(x2,y2)=(xF,yF)$

Substitute the values in the formula

$M=(\frac{xE+xF}{2},\frac{yE+yF}{2})$

Answer 2

I guess you are looking for a general way of writing a midpoint in coordinate system.
we have the following:
E(xe, ye) and F(xf,yf)
then mind point is as follows
((xe+xf)/2, (ye+yf)/2)