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lapo4ka [179]
3 years ago
9

Miles ordered 126 books to give away at the store opening. What is 126 rounded to the nearest hundred?

Mathematics
2 answers:
dlinn [17]3 years ago
3 0
Miles ordered 126 = rounded : 130
Yuliya22 [10]3 years ago
3 0
It would be 130. 

130 129 128 127 126 125 124 123 122 121 120.
^^^^                      <
This would be your asnwer
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The graph that best represents y = e x + 1 is what?
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I'ts 5x, 5x and then x = 1 is 2 and then y = e equals 3 and then 2x + 3 = 5x
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Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers
Mars2501 [29]

Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

Observe that

\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}

3 0
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3 years ago
Jessica and Riley are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping
bixtya [17]

Answer:

Cost of one roll of plain wrapping: \$5

Cost of one roll of holiday wrapping paper:  \$19

Step-by-step explanation:

Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.

Based on the information given, we can set up this system of equations:

\left \{ {{5p+13h=272} \atop {11p+16h=359}} \right.

In order to solve it, we can use the Substitution method. The steps are:

1. Solve for "p" from the first equation:

5p+13h=272\\\\5p=272-13h\\\\p=\frac{272-13h}{5}

2. Substitute the above into the second equation and solve for "h":

11(\frac{272-13h}{5})+16h=359\\\\598.4-28.6h+16h=359\\\\-12.6h=359-598.4\\\\h=\frac{-239.4}{-12.6}\\\\h=19

3. Substitute the value of "h" into p=\frac{272-13h}{5}:

p=\frac{272-13(19)}{5}\\\\p=5

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8 0
3 years ago
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