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4 years ago

Write 2 1/8 as an improper fraction

Mathematics

1 answer:

RoseWind [281]4 years ago

6 0

That would be 17/8
because you take 2 x 8 to get 16 then add the 1 and you get 17/8

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A unit rate is a value compared to how many units

Aloiza [94]

Answer:

When rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour

Step-by-step explanation:

Ex: If you have a multiple-unit rate such as 120 students for every 3 buses, and want to find the single-unit rate, write a ratio equal to the multiple-unit rate with 1 as the second term.

120/3 = 40/1

The unit rate of 120 students for every 3 buses is 40 students per bus. You could also find the unit rate by dividing the first term of the ratio by the second term.

8 0

3 years ago

(x-8)(2x+5)=0 solve the equation

dmitriy555 [2]

Answer:

x=8

Step-by-step explanation:

x= -5/2=-2 1/2= -2.5. If you add all of those up you will get x=8

<h2><em>Hope this helps and have a great day :)</em></h2>

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3 years ago

HELP ME QUICKLY PLS I WILL GIVE BRAINLYST

Vlad [161]

Your answer is B (9/10).

3 0

3 years ago

Read 2 more answers

8th grade math, please help.<br> I’ll give you brainliest if you want.<br><br> -Find the volume-

Bumek [7]

Answer:

113.10

Step-by-step explanation:

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3 years ago

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A certain system can experience three different types of defects. Let Ai (i = 1,2,3) denote the event that the system has a defe

andreev551 [17]

Answer:

(a) 0.5000

(b) 0.0833

((d) 0.9500

Step-by-step explanation:

Given that the following probabilities;

P(A1) = 0.12; P(A2) = 0.08,

P(A3) = 0.05; P(A1 ∪ A2) = 0.14, P(A1 ∪ A3) = 0.14,

P(A2 ∪ A3) = 0.11,

P(A1 ∩ A2 ∩ A3) = 0.01

(a) we want to find P(A2/A1).

P(A2/A1) = P(A1nA2)/P(A1)..........a

So we need to find P(A1nA2)

P(A1 ∪ A2)= P(A1) + P(A2) - P(A1nA2)

P(A1nA2) =P(A1) + P(A2) - P(A1 ∪ A2)

P(A1nA2) = 0.12 + 0.08 - 0.14

P(A1nA2) = 0.20- 0.14

P(A1nA2 )= 0.060

P(A2/A1) = 0.06/0.12

= 0.5000. (Ans)

(b) The required probability is: P(A2∩A3/A1) =[P(A2∩A3)∩P(A1)] /P(A1).........b

But [P(A2nA3)nP(A1)] = P(A1∩A2∩ A3)

P(A2∩A3/A1) = 0.01/0.12

P(A2∩A3/A1) = 0.0833 (Ans)

(Pr. of A1 defect) + (Pr. of A2 defect) + (Pr. of A3 defect)........c

Pr = 0.12 + 0.08 + 0.05

Pr = 0.2500 (And)

(d) The required probability is given by:

Pr[(A3)' /(A1∩A2)] = Pr[(A3)'nPr(A1∩A2)] /Pr(A1∩A2)]

Pr(A3)’ = 1 - Pr(A3) = 1 -0.05

Pr(A3)'/(A1∩A2)= (0.95×0.06)/(0.06)

Pr(A3)'/(A1∩A2 )= 0.95(Ans)......d

7 0

3 years ago