Base in your question that ask to find the Taylor series for function f(x) at a given value of A. And assume that F has a power series expansion. So to solve this you must first derive its function in to a standard series for taylor. Then after that you will came up with a solution of <span>Ts</span>=<span>c0</span><span><span>(x−a<span>)^0/</span></span><span>0! </span></span>+ <span>c1</span><span><span>(x−a<span>)^1/ </span></span><span>1! </span></span>+ <span>c2</span><span><span>(x−a<span>)^2/</span></span><span>2!</span></span>+<span>c3</span><span><span>(x−a<span>)^3/</span></span><span>3!</span></span>
The two digit numbers are 12
Answer:
-4
Step-by-step explanation:
Low tide is 1 ft below average water level.
High tide is 5 ft higher than low tide.
High tide is 5 ft higher than low tide. Start at low tide. Use 1 ft of the 5 ft to go up to average water level. You still have 4 ft more to go to high tide. That means high tide is 4 ft above average water level. Then, the average water level is 4 ft below high tide. A height below another height is is a negative number of feet from that height. Since the average water height is 4 ft BELOW high tide, then relative to high tide, the average water level is -4 ft.
Answer: -4
PLEASE MARK BRAINLEST!
Part A:
1 - yes, dilation
2 - no, shaded is 90 degree cc of non shaded
3 - yes dilation
Part B:
For part B, just plot the points.
For the dilated figure, multiply the x and y coordinates by 4.
Ex: V(-1, -1) --> V'(-4, -4)
It is an enlargement since the scale factor is greater than one.
Part C:
unshaded: X(-4, 4) Y(-4, -4) Z(4, -4)
Shaded: X(-1, 1) Y(-1, -1) Z(1, -1)
From shaded to unshaded it is 4, since nonshaded side length are 4x longer.
From unshaded to shaded it is 1/4 because shaded side lengths are 1/4 that of unshaded.
