Question

X^2-2x=0 solve by completing the square

Answer 1

X^2 -2x = 0
Get the coefficient of x
divide it by 2
square it
add it to both sides
-2 / 2 = -1
-1^2 = 1
x^2 -2x +1= 1
Take the square root of both sides
(x-1) = sq root (1)

Answer 2

First, halve the second coefficient (-2) and then square it: 
-2/2 = -1, (-1)^2 = 1, then add it to both sides:
$x^{2} -2x +1 = 1$
Now on the left side, we can rewrite this as:
$x^{2} - x - x + 1 = 1$
Factor out an x from the first two terms:
$x(x-1) - x + 1 = 1$
Factor out a -1 from the last two terms:
$x(x-1) - 1(x-1) = 1$
Now we can rewrite it as:
$(x-1)(x-1) = 1$
Which is equal to:
$(x-1)^{2} = 1$
Square root both sides, keeping in mind that leaves us with plus or minus one on the right:
$(x-1) = 1$
$(x-1) = -1$
Add one to both sides in both equations to solve for our two roots:
$x = 2, 0$