Answer:
Volume of a cylinder = πr²h
Given
V=81π
r=3
find h
Making h the subject
h= V/πr² = 81π/π(3)²
h= 81/9
h= 9cm
Step-by-step explanation:
We need to show whether

or

so we'll do either one of them,
we'll convert f(x) to f^-1(x) and lets see if it looks like g(x).

we can also write it as:

now all we have to do is to make x the subject of the equation.



now we'll interchange the variables

this is the inverse of f(x)

and it does equal to g(x)

Hence, both functions are inverse of each other!
This can be shown graphically too:
we can see that both functions are reflections of each other about the line y=x.
Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
Answer:
its the quotient of
Step-by-step explanation:
10/3= 3.333 and so on
Answer: a) 15 b)
Step-by-step explanation:
Let X be the number of days:
a)
For LESSONS:
Jordan does 10 / day ( 10*X)
Marco 5 / day ( 5*X)
Junyi 5 / day ( 5*X)
For TESTS:
Jordan does 5 / day ( 5*X)
Marco 10 / day ( 10*X)
Junyi 8 / day ( 8*X)
for each they need a total of 300
a)
days for the lessons
b)
days for the tests
so they need 15 days to finish both tasks
now if Junyi gets sick we just eliminate his contribution
a)
days for the lessons
b)
days for the tests
so in 20 days they will finish without him
If jordan works 10 hours a day, we just replace him with 10/24
a)
days for the lessons
b)
days for the tests
so at the end to complete both tasks they need 29.58 days