X-1/4x^2+7x+3 divided by 2x^2+4x-6/4x^2+11x+6

PLEASE HELP ME!!!! I WILL GIVE BRAINLIEST!!!!!!

Ivan

She buy 145 each all you do is divide 435 and 25

4 0

3 years ago

3) A local meteorologist measured the rain during a storm and recorded it on a graph. At what

ra1l [238]

Answer:

The rain fell at 2cm per hour

5 0

3 years ago

Read 2 more answers

A line on a coordinate plane passes through the point (2, -7) and has a slope of 0.75.

andrey2020 [161]

Answer:

Step-by-step Correct answer to the question This table gives a few (x, y)(x, y)left parenthesis, x, comma, y, right parenthesis pairs of a line in the coordinate plane

6 0

3 years ago

The zeros of a function are the values of for which the function is equal to zero. Enter a number in each blank to make true sta

olganol [36]

Answer:

Here we want to complete the blank to make the equality true:

( ) = (2 - 6)*(-4)

The equality is true if we have the same value in both sides, so we can think of this as an algebraic equation:

x = (2 - 6)*(-4)

We just need to find the value of x.

Then let's solve the right side:

x = (2 - 6)*(-4) = (-4)*(-4)

Remember the rule of signs:

(-)*(-) = (+)

x = (-4)*(-4) = 4*4 = 16

Then we need to complete the blank with the number 16

(16) = (2 - 6)*(-4)

5 0

3 years ago

a) How many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6?6x7x7=294 b) How many three-digit numbers

love history [14]

Answer:

a) 294

b) 180

c) 75

d) 168

e) 105

Step-by-step explanation:

Given the numbers 0, 1, 2, 3, 4, 5 and 6.

Part A)

How many 3 digit numbers can be formed ?

Solution:

Here we have 3 spaces for the digits.

Unit's place, ten's place and hundred's place.

For unit's place, any of the numbers can be used i.e. 7 options.

For ten's place, any of the numbers can be used i.e. 7 options.

For hundred's place, 0 can not be used (because if 0 is used here, the number will become 2 digit) i.e. 6 options.

Total number of ways = $7 \times 7 \times 6$ = 294

Part B:

How many 3 digit numbers can be formed if repetition not allowed?

Solution:

Here we have 3 spaces for the digits.

Unit's place, ten's place and hundred's place.

For hundred's place, 0 can not be used (because if 0 is used here, the number will become 2 digit) i.e. 6 options.

Now, one digit used, So For unit's place, any of the numbers can be used i.e. 6 options.

Now, 2 digits used, so For ten's place, any of the numbers can be used i.e. 5 options.

Total number of ways = $6 \times 6 \times 5$ = 180

Part C)

How many odd numbers if each digit used only once ?

Solution:

For a number to be odd, the last digit must be odd i.e. unit's place can have only one of the digits from 1, 3 and 5.

Number of options for unit's place = 3

Now, one digit used and 0 can not be at hundred's place So For hundred's place, any of the numbers can be used i.e. 5 options.

Now, 2 digits used, so For ten's place, any of the numbers can be used i.e. 5 options.

Total number of ways = $3 \times 5 \times 5$ = 75

Part d)

How many numbers greater than 330 ?

Case 1: 4, 5 or 6 at hundred's place

Number of options for hundred's place = 3

Number of options for ten's place = 7

Number of options for unit's place = 7

Total number of ways = $3 \times 7 \times 7$ = 147

Case 2: 3 at hundred's place

Number of options for hundred's place = 1

Number of options for ten's place = 3 (4, 5, 6)

Number of options for unit's place = 7

Total number of ways = $1 \times 3 \times 7$ = 21

Total number of required ways = 147 + 21 = 168

Part e)

Case 1: 4, 5 or 6 at hundred's place

Number of options for hundred's place = 3

Number of options for ten's place = 6

Number of options for unit's place = 5

Total number of ways = $3 \times 6 \times 5$ = 90

Case 2: 3 at hundred's place

Number of options for hundred's place = 1

Number of options for ten's place = 3 (4, 5, 6)

Number of options for unit's place = 5

Total number of ways = $1 \times 3 \times 5$ = 15

Total number of required ways = 90 + 15 = 105

7 0

4 years ago