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Alexxx [7]
3 years ago
9

A 16-ft ladder is placed 4 ft. from the base of a

Mathematics
2 answers:
Alex73 [517]3 years ago
8 0

Answer:

You have a right triangle.

a^2+b^2=c^2

4^2+b^2=256

16+b^2=256

b^2=256-16

b^2=240

b=sqrt240

b=15.49 ft. ans. for the height of the ladder up the wall.

Step-by-step explanation:

stepan [7]3 years ago
7 0

Answer:15.5

Step-by-step explanation:4^2 + h^2 = 16^2

h^2 = 256 - 16 = 240 = 16*15

h = 4 square root 15

h = 15.5

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Answer:

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Step-by-step explanation:

Like terms are ones that have the same variable, or that have no variable at all.

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There are two constant terms (with no variable). These are like terms.

The like term pairs are ...

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)
Lorico [155]

Answer:

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So, from equation (1) we can write that

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⇒ 6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3

⇒ 6\cos ^{2}x -3 = 3 - 6\sin ^{2} x

Hence, it is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x . (Answer)

5 0
3 years ago
The area of an ​20 -cm-wide rectangle is 440 cm. What is its​ length?
Nataly [62]

Answer:

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8 0
3 years ago
Takashi ran 200 yards in 40 seconds Ana ran 150 yards in 25 seconds can u tell who runs faster without rewriting the rates expla
Marina86 [1]
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Check:

Takashi: 200 divided by 400 equals 5 yd/sec
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7 0
3 years ago
Read 2 more answers
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