Perform the operation. (4x^2+9x-7)-(-7x^2+5x-1)
2 answers:
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πAnswer:
Therefore, the area of a sector of a circle would be 13.5π square units.
Step-by-step explanation:
Given
mi
- Ф = 60°
The area of a sector of a circle is:
A = π r² Ф/360
A = π (9)² 60/360
A = π 81 * 1/6
A = 13.5π square units
Therefore, the area of a sector of a circle would be 13.5π square units.