Let O be the point of intersection of diagonals.
Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.
In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6
Answer:
<em>x = 1</em>
This is the equation that I interpreted:
6/(x) - 3 = 3/(x)
I have never worked with determining extraneous equations before, so I cannot answer the second part.
It’s the 31 hope this helps you
